File SVG của tôi - TikZ to SVG

👤 17:48:48 - 02/01/2026

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Code TikZ:

            \begin{tikzpicture}
\tkzTabInit[lgt=2, espcl=3]
{$x$/1, $y'$/1, $y$/2}
{$-\infty$, $-1$, $1$, $+\infty$}

% dòng dấu y'
\tkzTabLine{,+,z,-,z,+,}

% dòng biến thiên y
\tkzTabVar{-/$-\infty$, +/$3$, -/$-1$, +/$+\infty$}
\end{tikzpicture}
        

👤 17:43:53 - 02/01/2026

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Code TikZ:

            \begin{tikzpicture}
\tkzTabInit[lgt=2, espcl=3]
{$x$/1, $y'$/1, $y$/2}
{$-\infty$, $x_1$, $x_0$, $x_2$, $+\infty$}

% dòng dấu y'
\tkzTabLine{,-,z,+,d,+,z,-,}

% dòng biến thiên y
\tkzTabVar{+/$+\infty$, -/$5$, +D-/$+\infty$/$-\infty$, +/$0$, -/$-\infty$}
\end{tikzpicture}
        

👤 15:04:32 - 24/11/2025

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Code TikZ:

            \begin{tikzpicture}[line join=round, line cap=round,>=stealth,thick,rotate=90,scale=0.8]
		% Hình phải
		\def\bk{3}
		\def\bkba{0.15}
		\def\bkbb{0.8}
		\def\ga{-50}
		\def\gb{180-\ga}
		\def\gc{0-\gb}
		\coordinate (O) at (0,0);
		\coordinate (M) at ($(O) + (\ga:\bk)$);
		\coordinate (N) at ($(O) + (\gb:\bk)$);
		\coordinate (I) at ($(M)!0.5!(N)$);
		\coordinate (J) at ($(O)+(M)-(I)$);
		\draw(M) arc (\ga:\gb:\bk);
		\path let \p1=(I),\p2=(M),\n1={scalar(veclen(\x2-\x1,\y2-\y1)/1cm)} in \pgfextra{\xdef\bke{\n1}};
		\fill[gray](M) arc (\ga:-90:\bk)--(I)--cycle;
		\draw(M) arc (\ga:\gc:\bk);
		\draw(M) arc (0:180:\bke cm and \bkba cm);
		\draw[dashed](M) arc (0:-180:\bke cm and \bkba cm);
		\coordinate (P) at ($(O) + (250:0.9*\bk)$);
		\coordinate (Q) at ($(O) + (235:1.1*\bk)$);
		\path(Q) node [below] {\Large\bf H};
		\coordinate (A) at ($(O) + (180:\bk)$);
		\coordinate (B) at ($(O) + (0:\bk)$);
		\coordinate (C) at ($(O) + (-90:\bk)$);
		\coordinate (D) at ($(O) + (90:\bk)$);
		\draw(B) arc (0:180:\bk cm and \bkbb cm);
		\draw[dashed](B) arc (0:-180:\bk cm and \bkbb cm);
		\draw[dashed](J)--(M)--(N) (C)--(D) (A)--(B);
		\draw[->](Q)--(P);
		\draw[->](C)--($(C)-(0,0.5)$)node[below]{$x$};
		\draw[->](B)--($(B)+(0.5,0)$)node[right]{$y$};
		\draw(A)--($(A)-(0.5,0)$) (D)--($(D)+(0,0.5)$);
		\path(O) node[below left]{$O$};
		\path(J) node[left=-3]{\tiny $3,5$};
		\path($(B)+(0.15,0)$)node[left]{\tiny $5,5$};
	\end{tikzpicture}
        

👤 15:03:02 - 24/11/2025

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Code TikZ:

            \begin{tikzpicture}[line join=round, line cap=round, >=stealth, thin]
  \tikzset{every node/.style={scale=0.9}}

  \draw[->] (-4.1,0)--(4.1,0) node[below left] {$x$};
  \draw[->] (0,-4.1)--(0,4.1) node[below left] {$y$};
  \draw (0,0) node[below left] {$O$};

  \foreach \x/\nx in {-4/-4, -3/-3, -2/-2, -1/-1, 1/1, 2/2, 3/3, 4/4}
    \draw[thin] (\x,1pt)--(\x,-1pt) node[below] {$\nx$};

  \foreach \y/\ny in {-4/-4, -3/-3, -2/-2, -1/-1, 1/1, 2/2, 3/3, 4/4}
    \draw[thin] (1pt,\y)--(-1pt,\y) node[left] {$\ny$};

  \begin{scope}
    \clip (-4,-4) rectangle (4,4);
    \draw[samples=200,domain=-3:3,smooth,variable=\x]
         plot (\x,{(\x)^3 + 3*(\x)^2 -4});
  \end{scope}
\end{tikzpicture}
        

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